20x^2-4x-24=0

Solution for 20x^2-4x-24=0 equation:

20x^2-4x-24=0

a = 20; b = -4; c = -24;
Δ = b2-4ac
Δ = -42-4·20·(-24)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-44}{2*20}=\frac{-40}{40}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+44}{2*20}=\frac{48}{40}
=1+1/5
$